Test Your SEO Skill With SEO Contest
In layman’s term, SEO contest is a competition participated by webmasters using a search engine’s web site pagerank system. Typically, the competition uses a nonsense and non-existent keyword for optimization. Several of the most known SEO contest keywords take the “hommingberger gepardenforelle”, “Busby seo Challenge” and the “Busby SEO Test”.
Typically, a contest is set up and a keyword is defined by the contest holder. The target of the contest then is to develop a website or a web page that is optimized for that keyword. The destination then is to obtain the 1st position rank for a search engine or some search engines for the given keyword.
In regular niches the competition is not as killing as in SEO contests, well… except for the search engine optimization niche off coarse. Only to be the best in an SEO contest you don’t always have to have a big wallet, or a huge network of authority web sites. You can also win with a good strategy, and good SEO tactic.
The number one for the search engine contest keyword phrase is always the one everybody is concentrated upon. And everything that page does is being repeated by hundreds of people. And that’s not what you wish, do you? You want to win by surprise. The best way is off course making the first spot a day before the end of the contest. But how can you do that? Well I’ll explain it to you.
Starting of all you need to get yourself indexed, get several low pagerank backlinks from some link directories or something. This is to recognize your position in the contest, once you rank at a spot for the specific key phrase you kind of know how hard it is going to be, if you place on the first 3 pages of Google the contest isn’t that hard. But if you rank at the tenth page it’s going to be a little more difficult.
The next thing is to use your network of web sites. You can do that by placing a link from each web site to your contest page. But if you have many web sites and many pages on those web sites, it can trigger a Google penalization, and you don’t want that in the contest. What you also can do is producing a page on every web site you own and link to that page from all the pages within the website. You will get high valuable links with a lot of weight because the links are on topic.
Many SEO contestants use blog because it can be a great source of helpful, fresh and dynamic contents. Furthermore, most search engines prefer blogs as compared to a common web site.
The history of SEO contest was considered to have recognized first on May 7, 2004 when SearchGuild sponsored the nigritude ultramarine challenge. The nigritude ultramarine SEO contest finished later on two months (July 7, 2004) and was won by Anil Dash - the company Vice President of Six Apart. When asked about what is his technique in winning the competition, Dash said that valid and informative contents are the name of the game. In addition, he also did not apply any black-hat optimization techniques in the contest.
Long term competitions have several the benefit and hurt of having to survive multiple Google updates.
Google updates make or break your competition entry. If you’ve involved in any black hat SEO, the more updates that you pass, the more likely it is that Google will discover your technique and penalize your site. A short term contest allows more flexibility in your seo technique. You can take your hat a little dirty and not be in much danger of loosing your ranking because of a Google punishment.
Andri R
http://www.articlesbase.com/seo-articles/test-your-seo-skill-with-seo-contest-683595.html
calling all math nerds test your skills i solved some but not all of these problems i made up contest type?
all right fellow nerds i have been trying to prepare for the international math olympiad and have solved problems from contests and such like the kind found on http://www.artofproblemsolving.com if you didnt visit i suggest u do as fast as possible theyve got great problems but anyway here are the some of the ones i made up either on my own or as modified versions of contest problems some of these i solved others still drive me batty so if you guys can solve any of these put up your solutions lets see what the competition is capable of these are in no particular orderas far as difficulty goes they likely wont fit in this form so there will be more
1.To "purify" a positive interger simply take the sum of its digits and keep doing so with each subsequent result until a 1 digit number is aqcuired find the smallest interger that can be purified in exactly 5 steps
next problems will come with additional details as they wont fit so dont think about going anywhere hold on 5 minutes and check back
2.An equilateral triangle has a line drawn from 1 of its vertices to the opposite side dividing it into 2 smaller triangles with inradii 3 and 4 find the length of the side of the equilateral triangle
3.let n be a positive interger less then or equal to 10 find the smallest positive interger that leaves a remainder of n-1 when divided by all possible values of n
4.Prove for all positive intergers n that the expression
n^n-(n-1)^(n-1)-(n-2)^(n-2)-…-1^1
is positive
5.10 cubes of side lengths 1 to 10 are clumped together in such a way as to minimize surface area whether inside or outside the new solid find that surface area
6.To "grow" an 2 digit number simply add the sum of its digits to the number and keep doing so until a 3 digit number is obtained. Finf the difference between the smallest and largest 2 digit numbers that can be grown in exactly 3 steps.
7.Given a sequence of positive intergers where each subsequent term except the first which is arbitrarily chosen is the sum of the squares of the digits of the previous. Prove that the terms in such a sequence of intergers will always come to repeat.
8.A cube of side length 10 has a hole drilled through it along its longest diagonal by a drill whose radius is 1. Find its new surface area.
common friends i aint seeing the enthusiasm
Let me attempt the first one. The only way to get one is to have the sum before it as 10 and the smallest one before it 19 and then smallest one before it is 199 and the smallest one before that is 19999999999999999999999 which is the answer.
So my sequence will be
19999999999999999999999
199
19
10
1
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I like the third one. The third one is simply lcm(1,2,3,4,5,6,7,8,9,10)-1 which is indeed 2519 because 2520 will give a remainder of 0 (or n if you think about it) so 2520-1=2519 will give a remainder of n-1.
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The fourth one is a piece of cake. It will take me longer to write here than it took me prove it. First we observe that for a positive integer k
(k+1)^k > k^k
and if k is bigger than 2 we have that
(k+1)*(k+1)^k > 2k^k
which then gives us that
(k+1)^(k+1) > 2k^k
Now to prove the original statement, we prove it by induction, for k=2, it is obviously true because
2^2-1^1=4-1=3>0 done
It is also true for k=3
3^3-2^2-1^2=27-4-1=22>0
Now assuming that the statement is true for some positive integer k, we have that
k^k-…-1^1>0
and we also have that (k+1)^(k+1)-2k^k>0 so we add them together and we get
(k+1)^(k+1)-k^k-…-1^1>0 and we are done.
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For the sixth one, the largest such number is 81 and the smallest such number is 65 so their difference is 16.
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For the 7th one, the sequence will either end up in
1,1,1,1,1,1…..
or it will start cycling
4, 16, 37, 58, 89, 145, 42, 20, 4,…
Look up happy numbers on wikipedia. They have been studied extensively.
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Eight is pretty easy too conceptually, the algebra is just a mess to write up. Okay, so, sides being ten give us the surface area is 600 and the length of the diagonal is sqrt(100+100+100)=sqrt(300).. After we drill the hole along the main diagonal ( I am assuming that the entire diagonal has been drilled out) we have lost two little circles on the corners each with diameter one. So each circle had area pi so we lost a total of 2pi from the original surface area from the two corners.
The hollow cylinder has height sqrt(300) and radius one, the inside surface area is 2*pi*sqrt(300) which is gained. So the new surface area is
600-2pi+2pi*sqrt(300).
References :
Good effort, I like these problems. But this is all I can solve right now.
Math Grad Student